Reverse the given number

 

Title: Reverse the given number

234 reverse number is 432

n%10= last digit of the number

n/10=last before digits

For example

234%10=4   [0*10+4=4]

234/10=23

23%10=3      [4*10+3=43]

23/10=2

2%10=2        [43*10+2=432]

2/10=0

Program:

n=int(input("Enter n value\n"))

r=0

t=n

while(t>0):

    r=(r*10)+(t%10)

    t=t//10

print("The reverse of ",n," is ",r)

Output:

            Enter n value

234

The reverse of  234  is  432