Armstrong number

 

Title: Check whether the given number is Armstrong or not

1¹=1

2¹=2

7¹=7

153=1³+5³+3³=1+125+27=153

The above all are Armstrong number

23=2²+3²=4+9=13 [23 is not armstrong]

Program:

n=int(input("Enter n value\n"))

r=0

t=n

c=0

while(t>0):

    c=c+1

    t=t//10

t=n

while(t>0):

    p=1

    for i in range(1,c+1):

       p=p*(t%10)

    r=r+p

    t=t//10

if(n==r):

    print(n,' is armstrong')              

else:

    print(n,' is not armstrong')

Output:

                >>>

Enter n value

153

153  is armstrong

>>>

Enter n value

4

4  is armstrong

>>>

Enter n value

23

23  is not armstrong